A study submarine has a 30-cm-diameter window that is 8.1 cm thick. The manufacturer claims the home window have the right to withstand also pressures up

The push at a details depth underwater is:

P = ρgh

P = pressure, ρ = sea water thickness, g = gravitational acceleration close to Earth, h = depth

The push exerted on the submarine window is:

P = F/A

P = push, F = pressure, A = area

The area of the circular submarine home window is:

A = π(d/2)²

A = location, d = diameter

Set the expressions for the push equal to each other:

F/A = ρgh

Substitute A:

F/(π(d/2)²) = ρgh

Isolate h:

h = F/(ρgπ(d/2)²)

Given values:

F = 1.1×10⁶N

ρ = 1030kg/m³ (pulled from a Google search)

g = 9.81m/s²

d = 30×10⁻²m

Plug in and also solve for h:

h = 1.1×10⁶/(1030(9.81)π(30×10⁻²/2)²)

h = 1540m

5 0
9 months ago

For your senior task, you would certainly like to construct a cyclotron that will certainly accelerate protons to 10% of the rate of light. The larg
DIA <1.3K>

The offered question is infinish. The finish question is as follows.

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For your senior project, you would prefer to develop a cyclotron that will certainly accelerate protons to 10% of the speed of light. The biggest vacuum chamber you have the right to discover is 60 cm in diameter.

What magnetic area toughness will you need?

Explanation:

Formula for the stamina of magnetic field is as follows.

B =

Here, m = mass of proton =

kg

v = velocity = 10% of

=
m/s

q = charge of proton =

= 30 cm = 0.30 m (as 1 m = 100 cm)

Therefore, magnetic area will certainly be calculated as follows.

B =

=

=

= 1.0437 T

Thus, we can conclude that magnetic area strength is 1.0437 T.

See more: Why Did The Color Of The Bromothymol Blue Change D In Your Control Tube?

7 0
11 months ago

If you lift a 250 N weight 3 meters off of the ground, how a lot work-related have you done in joules?
jeyben <28>
You have actually done 750 joules of job-related. force times distance=occupational. 250x 3=750
7 0
11 months ago

What is the mass of the object being weighed on the triple beam balance?
ss7ja <257>

jiyuushikan.org:The triple beam balance have the right to meacertain mass to the nearemainder tenth of a gram (0.1 g).

Explanation:

8 0
4 months ago

Two pposts are attracted to each other by the gravitational force between them. Ppost 1 has actually a mass of 12kg, Particle 2 has

jiyuushikan.org: 1.4 x 10^-8N

Explanation:

Given that,

Mass of Ppost 1 (m1) = 12kg

Mass of Particle 2 (m2) = 25kg

distance between pposts (r) = 1.2m. Gravitational force (F) =

Apply the formula for gravitational force:

F = Gm1m2/r²

wbelow G is the gravitational continuous through a worth of 6.7 x 10^-11 Nm2/kg2

Then, F = (6.7 x 10^-11 Nm²/kg² x 12kg x 25kg) / (1.2m)²

F = (2.01 x 10^-8Nm²) / (1.44m²)

F = 1.396 x 10^-8N (Rounded to the nearest tenth as 1.4 x 10^-8N)

Therefore, the magnitude of the gravitational pressure acting on the pposts is 1.4 x 10^-8 Newton

8 0
10 months ago
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