The push at a details depth underwater is:
P = ρgh
P = pressure, ρ = sea water thickness, g = gravitational acceleration close to Earth, h = depth
The push exerted on the submarine window is:
P = F/A
P = push, F = pressure, A = area
The area of the circular submarine home window is:
A = π(d/2)²
A = location, d = diameter
Set the expressions for the push equal to each other:
F/A = ρgh
F/(π(d/2)²) = ρgh
h = F/(ρgπ(d/2)²)
F = 1.1×10⁶N
ρ = 1030kg/m³ (pulled from a Google search)
g = 9.81m/s²
d = 30×10⁻²m
Plug in and also solve for h:
h = 1.1×10⁶/(1030(9.81)π(30×10⁻²/2)²)
h = 1540m
9 months ago
For your senior task, you would certainly like to construct a cyclotron that will certainly accelerate protons to 10% of the rate of light. The larg
The offered question is infinish. The finish question is as follows.
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For your senior project, you would prefer to develop a cyclotron that will certainly accelerate protons to 10% of the speed of light. The biggest vacuum chamber you have the right to discover is 60 cm in diameter.
What magnetic area toughness will you need?
Formula for the stamina of magnetic field is as follows.
Here, m = mass of proton =
v = velocity = 10% of
q = charge of proton =
r = radius =
Therefore, magnetic area will certainly be calculated as follows.
= 1.0437 T
Thus, we can conclude that magnetic area strength is 1.0437 T.
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11 months ago
If you lift a 250 N weight 3 meters off of the ground, how a lot work-related have you done in joules?
You have actually done 750 joules of job-related. force times distance=occupational. 250x 3=750
11 months ago
What is the mass of the object being weighed on the triple beam balance?
jiyuushikan.org:The triple beam balance have the right to meacertain mass to the nearemainder tenth of a gram (0.1 g).
4 months ago
Two pposts are attracted to each other by the gravitational force between them. Ppost 1 has actually a mass of 12kg, Particle 2 has
jiyuushikan.org: 1.4 x 10^-8N
Mass of Ppost 1 (m1) = 12kg
Mass of Particle 2 (m2) = 25kg
distance between pposts (r) = 1.2m. Gravitational force (F) =
Apply the formula for gravitational force:
F = Gm1m2/r²
wbelow G is the gravitational continuous through a worth of 6.7 x 10^-11 Nm2/kg2
Then, F = (6.7 x 10^-11 Nm²/kg² x 12kg x 25kg) / (1.2m)²
F = (2.01 x 10^-8Nm²) / (1.44m²)
F = 1.396 x 10^-8N (Rounded to the nearest tenth as 1.4 x 10^-8N)
Therefore, the magnitude of the gravitational pressure acting on the pposts is 1.4 x 10^-8 Newton
10 months ago
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