It takes a certain amount of **warm energy** or thermal power to revolve ice into water and also water into vapor.

You are watching: To melt 50 grams of 0-degree-celsius ice requires

When you heat a material, you are adding thermal kinetic power to its molecules and typically raising its temperature. The just exception is as soon as the product reaches its melting allude or boiling allude. At those two temperatures, the heat power goes right into transforming the state or phase of the material. After the state has actually readjusted, the temperature will rise aobtain through added thermal power.

The rate temperature transforms is the particular heat of the product. The amount of power compelled to melt the material is dubbed the latent warmth of melting. This all have the right to be shown in reflecting how a lot warmth is forced to readjust ice right into water and also then readjust the water into steam.

Questions you might have actually include:

What devices of measurement are supplied in turning ice into steam? How is specific heat used? How is latent warmth used?This leskid will answer those questions. Useful tool: Units Conversion

## Units of measurement

Since we are measuring the amount of warm compelled to make these transforms, we have to understand the definitions of the miscellaneous systems affiliated.

### Heat transfer

Heat is the total kinetic energy of all the molecules in an object. Although power is commonly measured in joules, a more widespread unit for warmth is the **calorie**, which is characterized as the amount of heat forced to readjust the temperature of 1 gram of water by 1 Celsius degree. Tright here is a conversion aspect to relate joules to calories, but we will not issue about that here.

**Note**: Calories are abbreviated as **cal** and grams as **g**. Also, **o****C** implies degrees Celsius.

In the English measurement system, they use the BTU (British thermal unit), which is the amount of heat compelled to readjust the temperature of 1 pound of water by 1 Fahrenheit level. The BTU is watched in the USA once referring to the capacity of a heating system.

### Specific heat

Materials vary in their capacity to save thermal energy. For example, a material like iron will warm up a lot much faster than water or lumber. The measurement of just how much warm is required to adjust the temperature of a unit mass of a substance by 1 level is dubbed its **specific heat**.

Tbelow are charts available listing the specific heat of various products. The chart below mirrors the particular warm of ice, water and steam in devices of calorie per gram-degree Celsius.

(Note that all items are noted with the exact same variety of decimal points. That suggests the exact same accuracy for each. Also, the zero in front of the decimal suggest assures that the reader will understand it is a decimal allude and also not a fly speck.)

State of water | Specific warm in cal/g-oC |

Ice | 0.50 |

Water | 1.00 |

Steam | 0.48 |

Specific heat of various claims of water

In various other words, it would certainly take twice as many kind of calories to warmth some water one degree than it would to warm the same mass of ice one level.

### Latent heat

When any material is heated to the temperature wright here it changes state, the temperature will reprimary the same till all the product alters state. That indicates ice water will remajor at 0oC (32oF) till all the ice is melted. The very same thing uses once cooling the products.

The reason is that power should be expended to adjust the state from solid to liquid or from liquid to gas. Likewise, power must be withattracted to change the state once cooling the material. The amount of power required is contact the **latent heat** of freezing or boiling. The chart below shows the latent warm or power forced to readjust the states of water.

Change of state of water | Latent warmth in cal/g |

Melting / Freezing | 80 |

Boiling / Condensation | 540 |

Latent warmth forced to change state of water

## Problem

A great way to understand the concepts is to fix a problem.

Suppose we have actually 50g of ice at -10oC. We want to warm the material until it all turns to steam at 110oC. How a lot warm is required?

With a difficulty that is complex favor this one, it is excellent to break it down right into pieces and settle each part individually. This additionally helps to describe the logic offered in the solution.

### 1. Heating ice

How much warmth would be compelled to raise 50g of ice to its melting point?The ice temperature need to be elevated 10 levels to reach 0oC.

Since the particular warm of ice is 0.50 cal/g-oC, that indicates that 0.50 calories is necessary to raise 1g of ice 1oC. Therefore, it would certainly take 50 x 0.50 calories to raise 50g up 1oC and 10 x 50 x 0.50 = **250 cal** to raise the ice to its melting point.

### 2. Melting ice

How a lot warmth would be forced to melt the 50g of ice?The latent warm for melting ice is 80 cal/g. That suggests that 1g of ice needs 80 cal of warmth to melt.

Thus, 50g requires 50 x 80 = **4000 cal** to melt.

### 3. Heating water

How much warmth is forced to heat 50g of water from 0oC to its boiling suggest of 100oC?Due to the fact that the particular heat of water is 1.00 cal/g-oC, that implies that 1.00 calorie is needed to raise 1g of water 1oC. Hence, it would take 50 x 1.00 calories to raise 50g up 1oC and also 100 x 50 x 1.00 = **5000 cal** to raise the water to its boiling allude.

### 4. Boiling water

How much warmth would certainly be required to boil the 50g of water?The latent heat for boiling water is 540 cal/g. That suggests that 1g of water requires 540 cal of heat to boil.

Therefore, 50g calls for 50 x 540 = **27000 cal** to boil.

### 5. Heating steam

How much heat is required to warmth 50g of steam from 100oC to 110oC?Because the specific warm of steam is 0.48 cal/g-oC, that indicates that 0.48 calories are required to raise 1g up 1oC. Hence, it would take 50 x 0.48 calories to raise 50g of vapor 1oC and also 10 x 50 x 0.48 = **240 cal** to raise the temperature of the vapor to 110oC.

### 6. Total

The complete warmth forced to readjust 50g of ice at -10oC to vapor at 110oC is:

250 + 4000 + 5000 + 27000 + 240 = **36490 cal**.

## Summary

Heating products like ice, water and also heavy steam rises their temperature. The certain warmth of the product determines the calories required to heat one unit of mass one level.

Changing the state of the product requires extra warmth power that is not offered to change the temperature. The amount of warmth required to change the state of the material is called its latent warmth. The complex problem of determining just how much warmth is forced to readjust ice into water and then adjust the water right into heavy steam must be damaged right into components and also solved individually.

See more: Why Can T Diabetics Use Heating Pads ? Why Can'T Diabetics Use Heating Pads

Heat up your thinking

## Reresources and also references

**Ron Kurtus" Credentials**

### Websites

**Specific Heat Equations** - Wolfram Science World

**Physics Resources**

### Books

(Notice: The School for Champions might earn comgoals from book purchases)

**Top-rated publications on Thermal Energy**

**Top-rated books on Physics of Temperature**

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