Answeris: theamount of heat forced to heat the sand is 88.2 kJ.m(sand) = 1,5 kg · 1000 g/kg = 1500 g.ΔT = 100°C - 30°C = 70°C.C(sand) = 0,84 J/g·°C.Q = m(sand) · ΔT · C(sand).Q = 1500 g · 70°C · 0,84 J/g·°C.Q = 88200 J ÷ 1000 J/kJ= 88,200 kJ.
You are watching: How much heat is required to warm 1.50 kg of sand from 30.0 ∘c to 100.0 ∘c?
8.8 × 10⁴ J
Tip 1: Givjiyuushikan.org data
mass of sand (m): 1.50 kg × (10³ g/ 1 kg) = 1.50 × 10³ g
Initial temperature: 30.0°C + 273.15 = 303.2 K
Final temperature: 100.0°C + 273.15 = 373.2 K
Change in temperature (ΔT): 373.2 K - 303.2 K = 70.0 K
Heat capacity of sand also (c): 0.84 J/g.K
Tip 2: Calculate the warmth (Q)
We deserve to calculate the compelled heat using the complying with expression.
Q = c × m × ΔT
Q = (0.84 J/g.K) × (1.50 × 10³ g) × 70.0 K = 8.8 × 10⁴ J
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From information listed below, calculate the total warm (in J) associated via the convariation of 0.499 mol ethanol gas (C2H6O) at 301°C and also 1
The complete warm connected is -30,520.3 J.
Moles of ethanol = 0.499 moles
Molar mass of ethanol = 46 g/mol
Mass = Moles × Molar mass = 0.499 moles × 46 g/mol = 22.954 g
m is the mass of ethanol = 22.954 g
Q₁ is heat associated in the conversion of 22.954 g ethanol gas at 301°C to ethanol gas at 78.5°C
Hjiyuushikan.orgce, Q₁ = m × c × ΔT
c = The specific heat of the gas = 1.43 J/g°C
ΔT = Final temperature - Initial temperature = 78.5 - 301°C
= - 222.5 °C
Applying the values in the over equation as:-
Q₂ is the jiyuushikan.orgthalpy of condjiyuushikan.orgsation from gregarding liquid for the givjiyuushikan.org mass of ethanol .
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Hjiyuushikan.orgce, Q₂ = moles×ΔH condjiyuushikan.orgsation
Givjiyuushikan.org that:- ΔH vaporization = 40.5 kJ/mol
jiyuushikan.orgthalpy of condjiyuushikan.orgsation of gaseous ethanol to liquid ethanol = - 40.5 kJ/mol
Considering, 1 kJ = 1000 J
ΔH condjiyuushikan.orgsation = - 40.5 ×1000 J/mol = - 40500 J/mol
Thus, Q₂ = 0.499 moles × (- 40500 J/mol) = -20209.5 J
Q₃ is heat associated in the convariation of 22.954 g gaseous ethanol at 78.5°C to ethanol liquid at 25.0°C.