We were told to rinse the buret through the base so that the concentration will not be messed up, but once it involves the flask that is going to organize the acid, tbelow is no need to rinse, bereason it would certainly not affect the result if it has actually water in it.

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Why is that? Wouldn"t the acid be diluted a little little and that throws off the accuracy?



The volume and also concentration of base amounts to the variety of moles of base. This is usage to identify the number of moles of acid in the flask. Since you are interested in the number of moles of acid in the flask, why would including water (which does not have any acid) change the variety of moles of acid?


Considering a direct titration:


You will certainly probably use a volumetric pipette to pass the acid solution to the erlenmeyer supplied on the titration, so the volume of acid is well-known (the specifically volume of the pipette).


Any distilled water you include to this erlenmeyer will certainly adjust its volume, but won"t adjust the amount of substance of acid inside it, neither the initial volume you included of the acid solution. Sometimes it"s even recommfinished that you include some water to make the shade adjust even more visible.

The objective of the titration is to find the volume of the base (of well-known concentration) necessary to neutralize the acid, and therefore, because you recognize the volume of acid included in the erlenmeyer (the pipette volume), calculate the concentration of the acid solution.

Water in the glass of the buret can cause variations in the concentration of the base being supplied, reason why we rinse it via the base, so we have actually an excellent precision titration. The erlenmeyer can be rinsed only via distilled water, since the volume of acid solution used for the calculation is continuous.

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You will have actually a equation that looks prefer this:

$$V( extbase) cdot c( extbase) = V( extacid) cdot c( extacid) cdot f$$

Wright here $V( extbase)$ is the volume of base consumed in the titration, $c( extbase)$ is the concentration of the base (which is known), $V( extacid)$ is the volume of the solution of acid added to the erlenmeyer (the volume of the pipette), $c( extacid)$ is the estimated concentration of the acid and also $f$ is the correction coreliable (so the actual acid concentration is $c( extacid) cdot f$).